prove that root of one- sintheta divided by one+sin theta=sectheta-tantheta where as acute
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Answer:
Firstly consider L.H.S; Now Rationalise.
√1+sin∅ √1+sin∅
------------×-----------
√1-sin∅ √1+sin∅
√(1+sin∅)² 1+sin∅
------------- = -----------
√1²-sin²∅ cos∅
Now consider RHS,
⇒sec∅+tan∅
⇒1/cos∅+sin∅/tan∅
⇒1+sin∅/cos∅
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