Question

Prove that : root of ( sec a - 1/ sec a + 1) + root of (sec a + 1/ sec a - 1) = 2 cosec a

Answer 1

sqrt((sec(A)-1)/(sec(A)+1)) + sqrt((sec(A)+1)/(sec(A)-1))
=
sec(A)-1 + sec(A)+1/ sqrt((sec(A)+1)*(sec(A)-1))   : fraction adding
=
2sec(A)/sqrt(sec^2(A)-1)           :sec square A -> sec^2(A) 
=
2sec(A)/sqrt((tan^2(A))
=
2sec(A)/tan(A)
=
2cosec(A)


HOPE IT HELPS YOU.......

Answer 2

Answer:

Step-by-step explanation: