Question

Prove that Root over (1+sin theta /1-sin theta) - sec theta =sec theta- root over (1-sin theta /1+sin theta)

Answer 1

Step-by-step explanation:

√1+sin0/1-sin0+√1-sin0/1+sin0

=2seeO

By taking L.H.S

√1+sin o/1-sin×1+sin o/1+sin+√1-sin×1-sin/1+sin

√(1-sin)^2/1^2-sin^20+√(-1sin0)^2/1-sin^20

√(1+sin0)^2/cos^2+√(1-sin0)^2/cos^20

1-sin0/cos0+1-sin0/cos0

1+sin0/cos0+1-sin0/cos0

2/cos0

2)cos0=2see0

R.H.S

hence proved

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