prove that root p +root q irrational p and q are prime numbers
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=> √q = a – √p Squaring on both sides, we get q = a2 + p - 2a√p => √p = (a2 + p - q)/2a, which is a contradiction as the right hand side is rational number, while √p is irrational. Hence, √p + √q is irrational.
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