prove that root2[pi/4-A]=cosA+sinA
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we know the formula
cos(a-b) = cos(a)cos(b) + sin(a)sin(b)
now
√2[cos(π/4 -A) ]
= √2 [cos(π/4)cos(A) + sin(π/4)sin(A)]
= √2[1/√2 cos(A) + 1/√2 sin(A)]
= √2*1/√2[cos(A) + sin(A)]
= cos(A) + sin(A)
Hence proved
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