Question

Prove that root3 is an irrational number.
Hence prove that 3 by 2 root 3 is an irrational number

Answer 1

Step-by-step explanation:

let 3/2√3 be rational and=a/b

3/2√3=a/b

1/2√3= a/3b

√3=3b/2a

hence LHS not equal to RHS hence √3 is irrational

Answer 2

Answer:

Step-by-step explanation:

Let us assume that √3 is a rational number.

then, as we know a rational number should be in the form of p/q

where p and q are co- prime number.

So,

√3 = p/q { where p and q are co- prime}

√3q = p

Now, by squaring both the side

we get,

(√3q)² = p²

3q² = p² ........ ( i )

So,

if 3 is the factor of p²

then, 3 is also a factor of p ..... ( ii )

Let p = 3m { where m is any integer }

squaring both sides

p² = (3m)²

p² = 9m²

putting the value of p² in equation ( i )

3q² = p²

3q² = 9m²

q² = 3m²

So,

if 3 is factor of q²

then, 3 is also factor of q

Since

3 is factor of p & q both

So, our assumption that p & q are co- prime is wrong

hence,. √3 is an irrational number

from this we get to know that 3 by 2 root 3 is an irrational number

as we have proven above that root 3 is irrational

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