prove that (root3-root2) is irrational
Answers
Step-by-step explanation:
If possible let root 3 is a rational number.
Therefore, root 3 = a/b , where a and b are co- prime integers .
that is, root 3 =a/b
Now,
squaring both side , we have ,
( root 3 )^2 = (a/b)^2
or, 3= a^2/ b^2.
or, a^2 = 3b^2
or, we can say.,
a^2 is divisible by 3
a is divisible by 3.
Again,
let, a=3c , where c is an integer .
a= 3c
squaring both sides
(a)^2= (3c)^2
or, a^2 = 9c ^2
or, 3b^2 = 9c^2 [ a^2 = 3b^2].
or, b^2= 3c^2
or, we can say,
b ^2 is divisible by 3
b is divisible by 3
Thus, a and b has no common factor other than 3.
also, a and b are divisible by 3.
There fore, our assumption is wrong.
Hence, root 3 is an irrational number.
In the same way find root 2 .