prove that (root3 + root5)whole square is an irrational number
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Solution ―
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Let √3 + √5 be rational
=> √3 + √5 - a , where a is rational
=> √3 = a - √5 ....... ( 1 )
on squaring both sides of equation ( 1 ) , we get
3 = ( a - √5 ) ^2 = a^2 +5 + 2√5a
=> √5 = a^2 + 2 / 2a
This is impossible because right hand side is rational , whereas the left hand side is irrational .
This is a contradiction .
Hence , √3 + √5 is irrational .
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Hope it's a helps you .
☺☺
-------------------------------------------------
Solution ―
++++++++++☺☺
Let √3 + √5 be rational
=> √3 + √5 - a , where a is rational
=> √3 = a - √5 ....... ( 1 )
on squaring both sides of equation ( 1 ) , we get
3 = ( a - √5 ) ^2 = a^2 +5 + 2√5a
=> √5 = a^2 + 2 / 2a
This is impossible because right hand side is rational , whereas the left hand side is irrational .
This is a contradiction .
Hence , √3 + √5 is irrational .
________________________________
Hope it's a helps you .
☺☺
Elisha15:
are you in lispeares slack ??
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