prove that root5 is irrational
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Answer:
let √5 = a/b
square on both sides
(√5)²=(a/b)²
5=a²/b²
hence, a²=5b² or b²= a²/5
now, let a= 5c
square on both sides
a²=(5c)²
5b² = 25c²
b² = 5c²
therefore, 5 is common in both situation
then, √5 is irrational
i hope this may help uhh
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