prove that rote3+rote 5 is irrational
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Step-by-step explanation:
let root 3+root 5 be a rational no and is equals to r where r is a positive integer
R3+R5=r
on squaring both sides [R=root]
(R3+R5)^2 = r^2
3+5+2R15=r^2
2R15=r^2-8
R15=(r^2-8)/2
since r is a positive integer and [r^2-8]/2 is rational no but since root 15 is an irrational no and equals to it so it contradicts the fact that root 3 + root 5 is rational hence root 3+ root 5 is irrational.
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