prove that s=u+v/2×t
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2
Answer:
if the area under the graph is the displacement, shouldn't s= (v-u)/2 x t because the area of a triangle is 1/2 b x h
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Answered by
1
Answer:
s= Area of the quadrangle (DOEB)
=Area of rectangle (DOEA) +Area of the triangle (DAB)
=(AE ×OE) +(1/2×AB×DA)
s= u+v/2×t
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