Question

prove that S=ut+1/2 at²​

Answer 1

Distance travelled = Area under the line

= ut + ½ (v-u)t

Acceleration (a) = (v-u)/t and so (v-u) = at

Therefore,

Distance travelled (s) = ut + ½ (v-u)t = ut + ½ (at)t = ut + ½ at²

Thus,proved.

Answer 2

Answer:

to prove s=ut+1/2 at²​

we know,

v=u+at........(i)

s=u+v/2 * t......(ii)

putting the value of v from equation (i) in equation (ii), we get

s= u+u+at/2 * t

or, s= 2u+at/2 * t

or, s= 2ut + at²​/2

or, s = 2ut/2 + at²​/2

or, s = ut + at²​/2

or, s= ut + 1/2 at²​

Explanation: