Question

prove that s=ut +1/2 at² using dimensional analysis​

Answer 1

Answer:

dimension of,

S- [L]

u- [LT^-1]

a- [LT^-2]

t- [T]

NOTE : Some constant are dimensionaless constant (I.e there value will be 1) like, all numbers, π, etc. and some constant have dimension like, planks constant, Universal gravitational constant, etc.

RHS :

ut + 1/2 at²

= [LT^-1] [T] + [LT^-2][T]²

=[L] + [L]

=[L] [2]

=[L]

LHS :

S - [L]

Hence, LHS = RHS.