Prove that s=ut+1/2at-2
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It can be proved by this statement
Area of velocity time graph gives us displacement .
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Explanation:
we know that v =dx/dt
vdt=dx
now in the above equation v is not independent of t. so we replace the value of v by v=u + at and get
(u + at)dt=dx
now integrating L.H.S AND R.H.S from limits o to t and xo to x respectively , we get u∫dt+a∫tdt=∫dx
⇒ ut+1/2at^2=(x-xo)
x=xo + ut + 1/2 at^2
x= ut + 1/2 at^2 (xo initial position = zero)
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