Math, asked by nikhikumar44, 11 months ago

prove that'scos15°-sin15°=1/√2

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Answered by Anonymous
0
Hi Mate!!!

Sin ( 15° ) = √3 -1 / 2√2

Cos ( 15° ) = √3 + 1 / 2 √ 2
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=>. Cos ( 15° ) - Sin ( 15° ) = √3 + 1 - √3 +1 / 2√2

=>. Cos ( 15° ) - Sin ( 15° ) = 2 / 2√2

=>. Cos (15°) - Sin ( 15 ° ) = 1 / √2

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Have a nice time....
Answered by Sudhir1188
0
Plz find the attachment for answers
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