prove that'scos15°-sin15°=1/√2
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Hi Mate!!!
Sin ( 15° ) = √3 -1 / 2√2
Cos ( 15° ) = √3 + 1 / 2 √ 2
..............................................................................
=>. Cos ( 15° ) - Sin ( 15° ) = √3 + 1 - √3 +1 / 2√2
=>. Cos ( 15° ) - Sin ( 15° ) = 2 / 2√2
=>. Cos (15°) - Sin ( 15 ° ) = 1 / √2
..............................................................................
Have a nice time....
Sin ( 15° ) = √3 -1 / 2√2
Cos ( 15° ) = √3 + 1 / 2 √ 2
..............................................................................
=>. Cos ( 15° ) - Sin ( 15° ) = √3 + 1 - √3 +1 / 2√2
=>. Cos ( 15° ) - Sin ( 15° ) = 2 / 2√2
=>. Cos (15°) - Sin ( 15 ° ) = 1 / √2
..............................................................................
Have a nice time....
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Plz find the attachment for answers
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