Question

Prove that
√(sec θ - 1 / cosθ + 1) + √(sec + 1 / sec θ - 1) = 2 cosecθ...

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Answer 1

Step-by-step explanation:

√secA-1/secA+1 + √secA+1/secA-1

=√(secA-1)²/sec²A-1 + √(secA+1)²/sec²A-1

=√(secA-1)²/tan²A+√(secA+1)²/tan²A

=(secA-1)/tanA+(secA+1)/tanA

=(secA-1+secA+1)/tanA

=2secA/tanA

=2.(1/cosA)(cosA/sinA)

=2cosecA

Answer 2

Step-by-step explanation:

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