Question

prove that sec-1/sec+1=(sin/1+cos)^2​

Answer 1

Answer:

PROVED

Step-by-step explanation:

L.H.S =(secA – 1)/ (sec A + 1)

(1/cosA - 1)/ (1/cos A +1)

(1 – cosA/cosA)/ (1 + cosA/cosA)

(1 – cosA)/ (1 + cosA)

Multiplying numerator and denominator by (1 + cosA), we get

(1 - cosA)(1 + cosA)/ (1 + cosA)²

(1 – cos²A)/ (1 + cosA)²

sin²A/ (1 + cosA)²

[ sinA/(1 + cosA) ]² = R.H.S

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