Prove that
Sec (1-sin A) (secA +tanA) = 1.
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Taking L.H.S,
= SecA(1-SinA)(SecA+tanA)
= 1/cosA x (1-sinA)(1/cosA + sinA/cosA)
= (1-sinA)/cosA x (1+sinA)/cosA
= 1-sin²A/cos²A
= cos²A/cos²A
= 1 R.H.S Proved
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