Math, asked by shaansingh1904, 1 year ago

Prove that-
sec(1-sinA)(secA+tanA)=1

Answers

Answered by Anonymous

8

Step-by-step explanation:

SecA(1-SinA)(SecA+tanA)

(1/CosA)(1-SinA)(1+SinA/CosA)

(1/Cos²A)(1-Sin²A)

(1/Cos²A)*Cos²A

Cos²A/Cos²A = 1

Answered by munnin1234

1

Answer:

Step-by-step explanation:

LHS:- 1-SINA/COSA ×1/COSA+SINA/COSA=(1-SINA)(1+SINA/COS^2A=1-SIN^2A/COS^2A=COS^2A/COS^2=1

LHS=RHS

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