Question

prove that sec^2 43 -cot^2 47=1​

Answer 1

Answer:

proved in the attachment below

Step-by-step explanation:

attachment given..

Answer 2

We know that,

$\sec(90 - theta) = \csc(theta) \\ \csc ^{2} (theta ) - \cot {}^{2} (theta) = 1$

from the above formula ,

sec^2 43 = cosec^47

Therefore,

sec^2 43 - cot^2 47 = 1

cosec^2 47 - cot^2 47 =1

1=1

LHS =RHS

Hence proved.