Prove that:
sec^2 (45° +0) - cot^2(45°- 0) /
sin (60° +0). sec (30° - 0)
= 1.
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We have,
cos
2
45
∘
sin60
∘
−cot30
∘
+15cos90
∘
=
(1/
2
)
2
2
3
−
3
+15×0=
3
−
3
+0=0
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