prove that sec^2(90°- a)- 1÷cot^2(90°-a)=1
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LHS
sec² ( 90 - a ) - 1 / cot² ( 90 - a )
= cosec²a - 1 / tan²a
= cot²a / tan²a { °.° cosec²a - 1 = cot²A }
= 1 / tan²a / tan²a { °.° cot²a = 1/tan²a }
= tan²a / tan²a
= 1
RHS
proved
sec² ( 90 - a ) - 1 / cot² ( 90 - a )
= cosec²a - 1 / tan²a
= cot²a / tan²a { °.° cosec²a - 1 = cot²A }
= 1 / tan²a / tan²a { °.° cot²a = 1/tan²a }
= tan²a / tan²a
= 1
RHS
proved
praveen55:
thank you
can you help me in another question
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