Math, asked by sonam6339, 2 months ago

prove that sec+3 tan=sec ti

Answers

Answered by saranshgaurn

2

Answer:

Given,theequationis

sec4θ−1

sec8θ−1

=

tan2θ

tan8θ

L.H.S:

sec4θ−1

sec8θ−1

=

cos4θ

1

−1

cos8θ

1

−1

=

(1−cos4θ)cos8θ

(1−cos8θ)cos4θ

=

2sin

2

2θcos8θ

2sin

2

4θcos4θ

=

2sin2θcos8θsin2θ

2sin4θcos4θsin4θ

=

2sin2θcos8θsin2θ

sin8θ2sin2θcos2θ

=

tan2θ

tan8θ

=R.H.S

henceproved.

Step-by-step explanation:

Answered by dakshkumar13

0

hay how are you

what's your age

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