Question

prove that sec^4A- sec^A=tan^2A+ tan^4A​

Answer 1

Step-by-step explanation:

sec^4A - sec ^2A

sec^4A - sec ^2A = sec^2A( sec^2A -1 )

sec^4A - sec ^2A = sec^2A( sec^2A -1 )= sec^A tan^2A

sec^4A - sec ^2A = sec^2A( sec^2A -1 )= sec^A tan^2A = ( tan^2A + 1 ) tan^2A

sec^4A - sec ^2A = sec^2A( sec^2A -1 )= sec^A tan^2A = ( tan^2A + 1 ) tan^2A = tan ^4A + tan^2A .

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