prove that
sec 70° sin 20° + cos 20° cosec 70º = 2
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Step-by-step explanation:
SEC 70* = COSEC 20* [BOTH ARE COMPLEMENTARY]
AND COS 20*=SIN 70* [BOTH ARE COMPLEMENTARY]
SO, COSEC 20*SIN20* + SIN 70*COSEC 70*
PUT COSEC 20* = SIN 20* [SINCE, COSEC = 1/SIN]
=COSEC 20*/COSEC 20*+SIN 70*/SIN 70*
= 1+1
= 2
HENCE PROVED
THANKS
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