Question

Prove that sec(90°-A)cosec (90°-A)=sec2(2means square)A cotA

Answer 1

Sec(90°-A)cot(90°A)
1/cos(90•-A)×1/sin(90•-A)
1/sinA×1/cosAcosA
Multiply by cosa up and down of the expression
Cos A/(cos A ×cos A) × 1/sin A
Then ,
Sec^2 A.cot A
Hence proved