Prove that
(sec A-1)
((sec A+1))
/(1-сos A)
((1+cos A))
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Answer:sec^2A
Step-by-step explanation:(secA-1)(secA+1)/(1-cosA)(1+cosA)
=sec^2A-1/1-cos^2A [{a+b}{a-b}=a^2+b^2]
=tan^2A/sin^2A
=sin^2A/cos^2A/sin^2A/1
=1/cos^2A
=sec^2A
Hope it may help you
NOTE : ^2 means square
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