Question

prove that :
sec a - 1 / sec a + 1 = (sin a / 1 + cos a )^2​

Answer 1

Answer:

don't no!!!!!!???????

Answer 2

Answer:

By breaking down LHS into terms of cos a, you will get 1-cos a/ 1+cos a

now by solving RHS,

sin^2 a / (1+cos a)^2 = 1-cos^2 a / (1+cos a)^2 (sin^2 a = 1-cos^2 a)

= (1-cos a)(1+cos a) / (1+cos a)(1+cos a) (a^2-b^2) = (a+b)(a-b)

now, (1+cos a) will cancel out from both numerator and denominator

so we are left with 1-cos a / 1+cos a

so we get LHS=RHS