prove that :
sec a - 1 / sec a + 1 = (sin a / 1 + cos a )^2
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Answered by
1
Answer:
don't no!!!!!!???????
Answered by
1
Answer:
By breaking down LHS into terms of cos a, you will get 1-cos a/ 1+cos a
now by solving RHS,
sin^2 a / (1+cos a)^2 = 1-cos^2 a / (1+cos a)^2 (sin^2 a = 1-cos^2 a)
= (1-cos a)(1+cos a) / (1+cos a)(1+cos a) (a^2-b^2) = (a+b)(a-b)
now, (1+cos a) will cancel out from both numerator and denominator
so we are left with 1-cos a / 1+cos a
so we get LHS=RHS
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