Math, asked by Aakash55555, 11 months ago

prove that sec A (1 - sin A) (sec A + tan A) = 1​

Answers

Answered by vjyupr4047gmailcom
1

Answer:

=sec A [sec A + tan A- (sec A sin A) -(tan A sin A)]

=sec A [sec A +tan A- tan A-(tan A sin A)]

=sec^2 A- tan ^2 A

=1

Answered by eramneelofer
1

Hey mate , here is your answer...

sec A (1-sin A)(sec A+tanA)

(sec A-sec A sinA)(sec A+tan A)

(sec A-sinA/cosA)(secA+tanA)

(secA-tanA)(secA+tanA)

sec^2 A -tan^2 A

We know that this value is equal to 1.

So,

sec A (1-sin A)(sec A+tan A)=1

Hence Proved.

Hope it helps....

PLZ MARK AS BRAINLIEST!!!

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