prove that sec A (1 - sin A) (sec A + tan A) = 1
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Answered by
1
Answer:
=sec A [sec A + tan A- (sec A sin A) -(tan A sin A)]
=sec A [sec A +tan A- tan A-(tan A sin A)]
=sec^2 A- tan ^2 A
=1
Answered by
1
Hey mate , here is your answer...
sec A (1-sin A)(sec A+tanA)
(sec A-sec A sinA)(sec A+tan A)
(sec A-sinA/cosA)(secA+tanA)
(secA-tanA)(secA+tanA)
sec^2 A -tan^2 A
We know that this value is equal to 1.
So,
sec A (1-sin A)(sec A+tan A)=1
Hence Proved.
Hope it helps....
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