Question

Prove that sec A (1 - sin A)(sec A + tan A) = '1.​

Answer 1

Answer:

L.H.S=secA(1−sinA)(secA+tanA)=(secA−cosAsinA)(secA+tanA)

=(secA−tanA)(secA+tanA)

=sec2A−tan2A

Putting if tan2A+1=sec2A−

we get L.H.S=1+tan2A−tan2A=1

⇒L.H.S=R.H.S

Answer 2

Step-by-step explanation:

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