Question

Prove that sec A ( 1- sin A) (secA + tan A) = 1 9. Prove that = 10 . Prove that = , using the identity sec2θ = 1+tan2θ.

Answer 1

Step-by-step explanation:

secA(1-sinA)(1/cos A+sinA/cosA)

secA(1-sinA)(1+sinA/cosA)

1/cosA(1-sin²A/cosA)

1-sin²A/cos²A=cos²A/cos²A=1 (sin²A+cos²A=1)

proved

sec²A=1+tan²A

sin²A+cos²A=1

dividing all term by cos²A

tan²A+1=sec²A