Question

prove that sec A.root 1-sin^A=1

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Answer 1

Answer:

Step-by-step explanation:

SecA.√ 1- sin²A= 1

( cos²A +sin²A =1

cos²A = 1 - sin²A

cosA = √ 1 - sin²A)

Solving LHS:-

1/cos × cos = 1 ( cos²A +sin²A = 1

cosA = √ 1 - sin²A)

Hence, LHS = RHS