Question

prove that ,sec A + tan A + 1 / secA - tanA + 1 = Cos A / 1 + sinA.​

Answer 1

Answer:

L.H.S = R.H.s

Explanation:

secA + tanA + cos A - tanA +1

Now squaring this whole equation

secA^2 + tanA^2 + cosA^2 - tanA^2 +1

(secA^2 + tanA^2) + cosA^2 - ( secA^2)... {identity no.3 of trigo}

1/cosA^2 + sinA^2/cosA^2 + cosA^2 - 1/cosA^2......{ secA^2= 1/ cosA^2 & tanA^2 = sinA^2/ cosA^2}

sinA^2/ cosA^2 + cosA^2- 1/cosA^2

sinA^2× 1/cosA^2 + cosA^2 - 1× 1/ cosA^2

sinA^2 + cosA^2 × 1/cosA^2 - 1/ cosA^2

sinA^2 + cosA^2

Now taking square root

sinA + cosA/1

Hence proved

Answer 2

Answer:

maths and English

Explanation:

266*5555**55588