Prove that (sec A+ tan A ) ( 1- sin A)=cos A
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(ꜱᴇᴄ ᴀ+ᴛᴀɴ ᴀ)(1-ꜱɪɴᴀ)
=(1/ᴄᴏꜱ ᴀ + ꜱɪɴ ᴀ/ᴄᴏꜱ ᴀ)(1-ꜱɪɴᴀ)
=[(1+ꜱɪɴᴀ)/ᴄᴏꜱᴀ](1-ꜱɪɴᴀ)
=(1+ꜱɪɴᴀ)(1-ꜱɪɴᴀ)/ᴄᴏꜱᴀ
=(1-ꜱɪɴ^2 ᴀ)/ᴄᴏꜱᴀ
=(ᴄᴏꜱ^2 ᴀ)/ᴄᴏꜱ ᴀ
=ᴄᴏꜱ ᴀ
Answered by
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Answer:
(sec A+tan A)(1-sinA)
=(1/cos A + sin A/cos A)(1-sinA)
=[(1+sinA)/cosA](1-sinA)
=(1+sinA)(1-sinA)/cosA
=(1-sin^2 A)/cosA
=(cos^2 A)/cos A
=cos A
Hence proved
... plz make it brain list
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