Prove that (sec A + tan A) (1 - sin A) =cos A
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Formulas used :
tan A = sin A / cos A
1 - sin²A = cos²A
cos A sec A = 1
Step-by-step explanation:
L.H.S
( sec A + tan A )( 1 - sin A )
⇒ ( sec A + sin A / cos A ) ( 1 - sin A )
⇒ [ ( sec A cos A + sin A ) / cos A ] ( 1 - sin A )
⇒ [ 1 + sin A ] ( 1 - sin A ) / cos A
⇒ ( 1 - sin² A ) / cos A
⇒ cos² A / cos A
⇒ cos A [ Proved ]
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