Prove that (Sec A - Tan A)²=
1-SinA/
1+SinA
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Refer to the attachment :)
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SecA= 1/cosA
TanA= SinA/CosA
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- Sin²A+cos²A=1
=> 1-Sin²A=Cos²A
- (a+b)(a-b)=a²-b²
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