prove that
sec A / tan A + cot A = sinA
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LHS cotA+tanA
=
sinA
cosA
+
cosA
sinA
=
sinAcosA
cos
2
A+sin
2
A
=
sinAcosA
1
{∵sin
2
x+cos
2
x=1}
=cosecAsecA
=RHS Hence proved
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