Question

Prove that secΦ+cosΦ can never be equal to 3/2

Answer 1

Answer:

secæ+cosæ

(1/cosæ)+cosæ

(1+cos²æ)/cosæ

let this be 3/2

(1+cos²æ)/cosæ=(3/2)

that makes,

cosæ=(2+2cos²æ)/3

this is not true.

this is raised from our assumption that secæ+cosæ=3/2.

so, secæ+cosæ≠3/2.