Prove that, (secθ +cosθ)(secθ-cosθ)-2+2cos²θ = tan²θ.sec²θ
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i m getting tan²theta*cos²theta
Amritas:
may I have the steps too
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Sum of interior opposite angles = exterior angle
25 ° + X =70 °
= 70 - 25 ° = 45 °
X=45°
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