Question

Prove
that (sec" o- sec²0) = tan²o + tanto​

Answer 1

Answer:

1is the answer

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Answer 2

Answer:

$\color{blue}{\boxed{Your answer}}$

(sec" o- sec²0) = tan²o + tanto

sec 0 +sec ^2 0 =2 sec 2^0

Tan^2+ tanto