prove that sec square theta + cos square theta can never be less than 2
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Answered by
8
using AM - GM
AM ≥ Gm
cos²θ + sec²θ / 2 ≥ √ cos²θ sec²θ
⇒ cos²θ + sec²θ ≥ 2 hence proved
hope this helps
AM ≥ Gm
cos²θ + sec²θ / 2 ≥ √ cos²θ sec²θ
⇒ cos²θ + sec²θ ≥ 2 hence proved
hope this helps
Answered by
3
here is your answer....
hope this would have been helped you a lot...
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