Prove that sec square theta + cot square (90-theta) =2 cosec square (90-theta) -1 ???
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Answered by
3
Answer:
Cot²(90-a)=tan²a
Cosec²(90-a)=sec²a
Sec²a+tan²a=2sec²a-1. (Sec²a-tan²a=1)
Sec²a+(sec²a-1)=RHS
2sec²a-1 =RHS
Hence proved
Answered by
1
Answer: sec²∅ + cot²(90-∅) = cot²( 90-∅ ) - 1
take L.H.S.
sec²∅ + cot²(90-∅)
sec²∅ + tan²∅ ( sec( 90-∅) = tan∅ )
sec²∅ + sec²∅ - 1
2sec²∅ - 1
2cosec²( 90-∅) - 1 ( sec∅ = cosec( 90-∅)
∴ L.H.S. = R.H.S.
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