Question

Prove that secθ + tanθ = cosθ /1-sinθ
​

Answer 1

Step-by-step explanation:

LHS =(secθ+tanθ)(1−sinθ)

=(

cosθ

1

+

cosθ

sinθ

)(1−sinθ)secθ=

cosθ

1

=

cosθ

(1+sinθ)(1−sinθ)

tanθ=

cosθ

sinθ

=

cosθ

1−sin

2

θ

((a+b)(a−b)=a

2

−b

2

)

=

cosθ

cos

2

θ

sin

2

θ+cos

2

θ=1

=cosθ ....identity.

=RHS