Question

Prove that sec + tan sec − tan = ( 1 + cos ) 2​

Answer 1

Answer:

We will be using the following:

(a+b)(a−b)=a2−b2

tan2(θ)+1=sec2(θ)

With those:

(sec(θ)+tan(θ))(sec(θ)−tan(θ))

=sec2(θ)−tan2(θ)

=(tan2(θ)+1)−tan2(θ)

=1

Step-by-step explanation:

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