Prove that sec theta + cos theta can never be equal to 3/2
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How can you prove that sec theta+cos theta is not equal to 3/2?
Well let’s try to find out what happens if it can be equal to 3/2
We will have
secθ+cosθ=32⟺
1cosθ+cosθ=32⟺
1+cos2θ=3cosθ2⟺
2+2cos2θ=3cosθ⟺
2cos2θ−3cosθ+2=0
The above equation has no real solutions for cosθ since the discriminant of the quadratic equation is
Δ=(−3)2–4⋅2⋅2=9−16=−7<0
So there is non way secθ+cosθ=32
therefore
secθ+cosθ≠32
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