Question

Prove that (sec theta+cos theta)(sec theta+cos theta)=tan^theta+sin^theta​

Answer 1

Step-by-step explanation:

LHS=(secθ+cosθ)(secθ−cosθ)

=sec

2

θ−cos

2

θ

=(1+tan

2

θ)−(1−sin

2

θ)

=tan

2

θ+sin

2

θ

=RHS

Hence proved