Question

Prove that
Sec theta / tan theta + cot theta = sin theta

Answer 1

Refer to the attachment

Answer 2

sec/ tan + cot = sin

=>$\dfrac{1}{cos}$/$\dfrac{sin}{cos}$+$\dfrac{cos}{sin}$=sin

=>$\dfrac{1}{cos}$/$\dfrac{sin}{cos}$+$\dfrac{cos}{sin}$

=> $\dfrac{1}{cos}$/$\dfrac{sin(sq)+cos(sq)}{cos × sin}$

=>$\dfrac{1}{cos}$/$\dfrac{1}{cos×sin}$

=>$\dfrac{cos × sin}{cos}$

${\therefore{sin}$=RHS