Question

prove that Sec thita- tan thita /sec thita+tan thita = 1-2 sec thita tan thita + 2 tan²thita​

Answer 1

Answer:

(secθ−1)

2

tan

2

θ

=

(secθ−1)

2

sec

2

θ−1

=

(secθ−1)

2

(secθ−1)(secθ+1)

=

secθ−1

secθ+1

=

cosθ

1

−1

cosθ

1

+1

Multiply numerator and denominator with cosθ, we get

=

1−cosθ

1+cosθ

, Hence proved