Prove that sec x - cos x = sin x tan x
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Answer:
put secx=1/cosx and take LCM
(1/cosx)-cosx=1-cos^2x/cosx
=sin^2x/cosx
=(sinx×sinx)/cosx
=sinx×tanx....
hence proved
Answered by
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Step-by-step explanation:
1. RHS : sec x - cos x
we know that Sec is inverse of cos.
Replacing sec with 1/cosx
2. 1/cos x - cos x
LCM is cos x
3. (1 - cos x × cos x) / cos x
4. (1 - cos ^ x)/cos x [ Cos ^ x is cos sq. x]
5. sin^x / cos x (since 1-cos^x = sin^x)
6. (sin x × sin x )/ cos x
since Sin x/cos x = tan x
replacing
tanx sin x = RHS
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