Prove that Sec²(90°- A) -
1/tan²A =1
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Answer:
LHS
sec² ( 90 - a ) - 1 / cot² ( 90 - a )
= cosec²a - 1 / tan²a
= cot²a / tan²a { °.° cosec²a - 1 = cot²A }
= 1 / tan²a / tan²a { °.° cot²a = 1/tan²a }
= tan²a / tan²a
= 1
RHS
proved
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